Quantative Analysis Multiple Choice Questions
Autor: Kevin Simmons • April 12, 2019 • Course Note • 657 Words (3 Pages) • 675 Views
David Rivas
19 LW MANA 6302
Quantitative Analysis MC questions
- A professor claims that his students have the above average intelligence. So then we take a random sample of 30 of students IQ score and find a mean of 112. The mean population IQ is 100 with a standard deviation of 15.
- Reject H0. The students have above average intelligence.
- Do not reject H0.. The students do not have above average intelligence.
- Not enough information
- The Apple ecosystem says that customers who own an IPhone have a must have 2 other Apple products. By polling 30 customers at an Apple store they found the mean of customers with an IPhone and two other Apple products to be 13 with a standard deviation of 17. Apple research believes that adding a one-year free subscription to apple music will increase sales with the purchase of two apple products.
- Do not reject H0.. Apple Customers who own an IPhone have 2 other Apple products
- Reject H0. Apple Customers who own an IPhone do not have 2 other Apple products.
- When testing a hypothesis about two population means and the t distribution is used which of the following assumptions is required? (Basic Business Stats)
a. Both the population means are the same
b. Standard deviations are not the same
c. Sample sizes are equal
d. Both population means are normally distributed
- Which statistical distribution is used for testing the difference between two population variances? (Basic Business Stats)
a. Z
b. F
c. t
- What can we derive from the one-way Anova results seen below? (Alpha level 0.05)[pic 1]
a. F value is greater than F critical so we accept the null hypothesis.
b. Both F value and F critical are greater than the selected alpha so we reject the null hypothesis.
c. Since the P-value is less than the alpha level we reject he null hypothesis.
d. Both b and c.
e. None of the above.
Answers:
Question 1
Step 1: State the hypotheses
H0: μ = 100
H1: μ >100
Step 2: Compute the test value
[pic 2]
z= (112-100) / (15 / 30) = 4.38
Step 3: Z critical value
df = n-1 = 100-1 = 99
Area in 1 tail, α = 0.05
z-crit = 1.660
Step 4: We reject Ho.[pic 3]
[pic 4]
[pic 5][pic 6][pic 7]
[pic 8]
[pic 9]
[pic 10]
Step 5: We reject the null hypothesis and accept the alternate hypothesis that students do have above average intelligence.
Answer
...