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Cven 3501 - the Bureau of Meteorology

Autor:   •  May 6, 2018  •  Case Study  •  2,421 Words (10 Pages)  •  716 Views

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Β CVEN3501 - Assignment 1 2018

Question 1:Β Penman Monteith Evapotranspiration

Firstly, it must be noted that no data for January 2017 was available since the Bureau of Meteorology only displays data for the past 14 months. January 2018 data was used in its place, however, on 4thΒ January 2018 data was missing for Sydney (station number 066062) and previous days were also missing data and hence a linear interpolation could not be undertaken. As a result, neighbouring station Sydney Airport AMO (station number 066037) was used for the entirety of this assignment.

Given the meteorological data for 4thΒ January 2018 at Sydney Airport AMO, NSW using station 066037 (8.8km from Sydney) located at Latitude 33.95 S and Longitude 151.17 E, the following variables were calculated.

Mean Wind Speed:

Assumptions: Wind speed measurements made at 10m height and that the average wind speed is equal to the average of 9am and 3pm wind speeds.

𝑒10


= 𝑒9π‘Žπ‘š + 𝑒3π‘π‘š

2[pic 1]

ln (Β Β Β Β Β Β Β Β 2Β Β Β Β Β Β Β Β )[pic 2]

𝑒2 = 𝑒10Β _Β Β Β Β Β Β Β Β 0.0023

𝐼𝑛 (Β Β Β Β Β Β Β Β 10Β Β Β Β Β Β Β Β )[pic 3]

0.0023

Mean Temperature:

Assumptions: Mean temperature is equal to the mean of the minimum and maximum temperatures observed.

π‘‡π‘šπ‘’π‘Žπ‘›


= π‘‡π‘šπ‘Žπ‘₯ + π‘‡π‘šπ‘–π‘›

2[pic 4]


Saturated Vapour Pressure:

𝑒𝑠


= [𝑒(𝑇max) + 𝑒(𝑇min)]

2[pic 5]

𝑒 = 0.6108𝑒 ( Β 17.27𝑇 )[pic 6]

237.3 + 𝑇

Actual Vapour Pressure:

Assumptions: Maximum and Minimum Relative Humidity is equal to the 9am and 3pm Relative Humidity measurements respectively.

π‘’π‘Ž


= (𝑒(𝑇min) π‘₯ 𝑅𝐻maxΒ + 𝑒(𝑇max) π‘₯ π‘…π»π‘šπ‘–π‘›)

2[pic 7]

Vapour Pressure Deficit:

𝑉𝑃𝐷 = (π‘’π‘ Β βˆ’ π‘’π‘Ž)

Top of Atmosphere Radiation:

𝑅 = 118.1 𝑑

[pic 8]


[𝑀


𝑠𝑖𝑛(πœ‘) 𝑠𝑖𝑛(𝛿) + π‘π‘œπ‘ (πœ‘) π‘π‘œπ‘ (𝛿) 𝑠𝑖𝑛(𝑀 )]

π‘ŽΒ Β Β Β Β Β Β Β πœ‹


π‘ŸΒ Β Β Β Β Β Β Β π‘ 


πœ‘π‘Ÿπ‘Žπ‘‘


= πœ‹ 180


𝑠

π‘₯ πœ‘[pic 9]

𝑑 Β = 1 + 0.033 π‘π‘œπ‘  (2πœ‹ +  𝐽 )[pic 10]

π‘Ÿ

𝛿 = 0.4903 𝑠𝑖𝑛 (2πœ‹ π‘₯        𝐽[pic 11]

365


365

βˆ’ 1.405)

π‘Šπ‘ Β = π‘Žπ‘Ÿπ‘π‘π‘œπ‘ [π‘‘π‘Žπ‘›(πœ‘) π‘‘π‘Žπ‘›(𝛿)]


Incoming Solar Radiation:


𝑛

𝑅𝑠 = π‘…π‘ŽΒ (0.25 + 0.5 𝑁)[pic 12]

...

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