Stats for Management
Autor: Kshitij Sankhe • October 17, 2016 • Case Study • 348 Words (2 Pages) • 630 Views
STATISTICS FOR MANAGEMENT
PROBLEMS ON PROBABILITY AND DISTRIBUTIONS
ANSWERS
1. 7/9
2. 0.048
3. 0.2872
4. (a) (0.75)n, (b) 0.288
5. (a) 0.44, (b) 0.404, (c) 0.8982, (d) 0.5556
6. (a) 0.83, (b) 0.086, (c) 0.506, (d) 0.232, (e) 0.08
7. (a) 0.7, (b) 0.3413, (c) (I) 0.692, (II) 0.4878
8. (a) 0.7, (b) 0.25, (c) 0.8673
9. (a) 0.8, (b) 0.7, (c) 0.4286, (d) 0.2143, (e) 0.6
10. (a) 0.3888, (b) 0.2496
11. (a) 0.37, (b) 0.5556, (c) 0.246, (d) 0.214, (e) 0.410, (f) 0.789
12. (a) 0.1, (b) 0.6, (c) 0.3
13. 0.271
14. (a) 0.5, (b) 0.3085, (c) (i) 1.8904, (ii) 0.5217
15. (a) 0.21, (b) 0.8037, (c) 7.82
16. 2.407
17. (a) 0.4, (b) 0.2712
18. (a) 0.3, (b) 5.36
19. 0.1798, 0
20. E(Y – X) = 1, P(Y=3) = 0.375
21. (a) 0.0658, (b) 0.5391, (c) 1.5, (d) 6
22. k = 0.5, a = 2/3, median = (2/3)+[pic 1], conditional probability = 5/8
23. (a) 2, (b) 0.9647, (c) 0.1856
24. (a) 0.8917, (b) 0.4762, (c) 0.8
25. 0.4667
26. 1.125
27. (i) 0.48, (ii) 0.4828
28. P(X=0)= 0.336, P(X=1)= 0.452, P(X=2)= 0.188, P(X=3)= 0.024,
E(X)= 0.9, V(X) = 0.61
29. (a) 0.91, (b) 0.335, (c) 0.78, (d) 0.2271
30. (a) 3/16, (b) 9/16, (c) 3/16, (d) 37/16, (e) 0.7148, (f) 27/16
31. (a) 0.5, (b) 2/3, (c) 2.5, (d) 0.25, (e) 2.3, (f) 7
32. (a) 0.189, (b) 0.095, (c) 1.98, (d) 0.235
33. (a) 0.3278, (b) 0.4891
34. (a) 7/24, (b) 26/9, (c) 77/192, (d) 49/576, (e) 1/2
35. (a) 0.2682, (b) (i) 0.1571, (ii) No, (c) Yes, by Chebycheff’s inequality,
(d) mean = – 1.2427, standard deviation = 5.6513
36. (a) 0.7240, (b) 0.4, (c) 0.3125
37. (a) 1.4586, (b) 0.8028, (c) 0.9, (d) 65.667
38. (a) 0.4651, (b) 1/3, (c) 3/64, (d) 12.96, (e) 1.71
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