Aqm Homework

Performing one way Anova Test

Here we will perform one way anova test using SPSS to find out any statistically significant difference between the means of three age groups. Six steps is used to complete our hypothesis testing.

Compliance

Step One: The Null and the Alternate Hypothesis 

H0 : μ<20 = μ20-29= μ30-49

H1 : The means are not all equal.

Step Two (Level of Significance): 95% Level of confidence, α = 0.05

Step Three (The Test Statistic):Anova test using SPSS.

Step Four: Decision Rule.           Reject H0 if        F > Fα,k-1,n-k

Reject H0 if p-value < significance level.

Step Five: Making a Decision

[pic 1]

Failed to reject H0 because 1.684 (F value from SPSS Anova test) is less than 3.07 (F critical value from F ditribution table). Also the p-value is greater  than sgnificent level (.191> .05)

Step Six: Interpreting the Result: Based on the evidence, We conclude that The population means are all equal. The mean scores are same for the three age groups.

Assurance

Step One: The Null and the Alternate Hypothesis 

H0 : μ<20 = μ20-29= μ30-49

H1 : The means are not all equal.

Step Two (Level of Significance): 95% Level of confidence, α = 0.05

Step Three (The Test Statistic):Anova test using SPSS.

Step Four: Decision Rule.           Reject H0 if        F > Fα,k-1,n-k

Reject H0 if p-value < significance level.

Step Five: Making a Decision

[pic 2]

Failed to reject H0 because .376 (F value from SPSS Anova test) is less than 3.07 (F critical value from F ditribution table). Also the p-value is greater  than sgnificent level (.688> .05)

Step Six: Interpreting the Result: Based on the evidence, We conclude that The population means are all equal. The mean scores are same for the three age groups.