Bottling Company Case

As the president of the Stetson Bottle Company, I have been receiving complaints from customers on the quantity of product received when purchasing our sixteen ounces soda bottles. These claims have caused my boss to worry and would like me to investigate the issue at hand. I will begin my investigation by instructing the employees to pull at random 30 bottles from all the shifts at the bottling plant. By random containers all shifts, I can eliminate the possibility of if being a human error. To start my investigation, I begin by weighing the sample size of 30 bottles. The weight ranges between 14 oz. And 16.1oz., which lets me know there is a problem with our bottling consistence. For more detailed information to complete my investigation, I must calculate the Mean, Median, and Standard Deviation of the sample size.

* The Mean is the sum of the sample size in ounces divided by sample size. Based on the sample size of 30 bottles, there is a total of 446.1 ounces divided by the sample size of 30, gives is the mean of 14.87. = 14.87The Median is the data set middle number when the set sorted in numerical order. Median of the 30 bottles is 14.8.

* Standard deviation is the measure of how spread out the numbers is. To find the (Standard Deviation), you must find the square root of the variance. The 0.5503.

The Stetson Bottling Company is very optimistic of its bottling process. I will now construct the Confidence Interval of the ounces in the bottles at a 95%. The Confidence Interval describes the amount of the uncertainty associated with the sample estimate of the population parameter. By using the already discovered the information above me computed the Confidence Interval.

14.673 ≤ μ ≤ 15.067

My next course of action was to complete a hypothesis testing of the data discovered. The hypothesis testing will verify if the claim that a bottle contains less than sixteen (16) ounces supported. The