Business Stat
Autor: cruzlok • April 25, 2015 • Coursework • 924 Words (4 Pages) • 779 Views
GROUP 2
CHAN KA LOK
50966632
MC
- B
- A
- D
- C
- D
- B
- D
- C
- D
- A
- B
- A
- A
- B
- D
- D
- B
LQ
1)
There are 25 people conducted this survey and 11 people rated 50 or below.
11/25 x 100%
=44.0000%
The percentage of the respondents rated overall television quality with a rating of 50 or below is 44.0000%.
2)
Let A be the number of the residents own 2 cars.
Let A’ be the number of the residents not own 2 cars.
Let B be the number of the residents’ annual household income is over $25,000.
Let B’ be the number of the residents’ annual household income is not over $25,000.
P (A l B) = P (A and B)/ P (B)
0.8 = P (A and B)/ 0.6
P (A and B) = 0.4800
Event | A | A’ | Total |
B | 0.4800 | 0.1200 | 0.6000 |
B’ | 0.2200 | 0.1800 | 0.4000 |
Total | 0.7000 | 0.3000 | 1.0000 |
The probability that the residents of a household do not own 2 cars and have an income over $25,000 a year is 0.1200.
3a)
We have to prove P (A and B) = P (A) P (B)
L.S = P (A and B)
= 0.4800
R.S = P (A) P (B)
= 0.7000 x 0.6000
= 0.4200
L.S =/ R.S
The events of the residents of a household own 2 cars and income over $25,000 a year are not statistically dependent.
3b)
We have to prove P (A and B) = 0
L.S = P (A and B)
= 0.4800
=/ R.S = 0
The events of the residents of a household own 2 cars and income over $25,000 a year are not mutually exclusive.
3c)
We have to prove P (A or B) = 1
L.S = P (A or B)
= P (A) + P (B) – P (A and B)
= 0.7000 + 0.6000 – 0.4800
= 0.8200 =/ R.S =1
The events of the residents of a household own 2 cars and income over $25,000 a year are not collectively exhaustive.
4i)
Let A be the number of student who did well on the Midterm.
Let A’ be the number of student who did poorly on the Midterm.
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